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What real number that should be added to the polynomial f(x)=81x^2-31, so that it is exactly divisible by 9x+1?(a) 40(b) 10(c) 30(d) 20The question was posed to me by my school teacher while I was bunking the class.Enquiry is from Division of Polynomial in portion Polynomials of Mathematics – Class 10

Answer»

The correct option is (c) 30

For explanation I would say: 81x^2-31 is exactly DIVISIBLE by 9x+1

Hence, on dividing 81x^2-31 by 9x+1

We get, 9x-1 as QUOTIENT and REMAINDER as -30.

So if we add 30 to 81x^2-31, it will be exactly divisible by 9x+1.



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