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If `f(x) = [x] [sinx]` in `(-1,1)` then f(x) isA. continuous on (-1,0)B. differentiable on (-1,1)C. differentiable at x=0D. none of these |
Answer» Correct Answer - A We have `f(X)=[x sin x]={{:(,-1xx -1=1,"if "-1 lt x lt 0),(,0xx0,"if "0 le x lt 1):}` Clearly, f(x) is not continuous at x=0. Consequently it is not differentiable at x=0 Since f(x) is constant function on `(-1,0) uu (0,1).` Som it is continuous and differentiable on `(-1,0) uu (0,1).` |
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