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| 1. |
If Gcf (25,15) =4× +1 then ×=_ |
| Answer» 25 = 5\xa0× 515 = 5\xa0× 3G.C.F (25,15) = 5G.C.F\xa0(25,15)= 4X+14x + 1 = 54x = 5 - 1\xa04x = 4x = 4/4x = 1 | |