If H.C.F (25,15)= 4X+1 then x=

1.	If H.C.F (25,15)= 4X+1 then x=
Answer» 25 = 5\xa0× 515 = 5\xa0× 3H.C.F (25,15) = 5H.C.F (25,15)= 4X+14x + 1 = 54x = 5 - 1\xa04x = 4x = 4/4x = 1 Find hcf and substitute

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