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If HCF (6,a) = 2 and LCM (6,a) = 60 then Find the value of a. |
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Answer» LCM x HCF= Product of two numbers60 x 2 = 6 x a120 = 6aTherefore, a = 20 Since, LCM × HCF = Product of two numbers60 × 2 = 6 × a120 = 6a6a = 120a = 120/6=20 A=20 20 HCF *LCM=a*b 2*60=6*aa=2*60/6a=20 |
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