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| 1. |
If hcf of 210 and 55 is expressible in the form 210×5+55p,find p |
| Answer» 210 = 2 x 3 x 5 x 755 = 5 x 11Therefore, HCF (210, 55) = 5Now, 210 x 5 + 55 x p = 5=> 1050 + 55p = 5=> 55p = 5 - 1050=> 55p = -1045=> p = -1045/55=> p = -19 | |