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If HCF of 408 & 1032 is expresible in 1032p - 408 * 5 find p

Answer» If the HCF of 408 and 1032 can be written as\xa0By Euclid \'s division algorithm,1032 = 408×2 + 216408 = 216×1 + 192216 = 192×1 + 24192 = 24×8 + 0Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24Now,\xa01032x - 408*5 = HCF of these numbers⇒ 1032x - 2040 = 24⇒ 1032x = 24+2040⇒ x = 2064/1032⇒ x = 2So value of x is 2.


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