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| 1. |
If HCF of 408,1032 is written in the form of 1032x - 408x5 then find x |
| Answer» Very low-quality question.Solution: HCF of 408 and 1032 is 24=>\xa01032x - 408x5 = HCF=> 1032x - 2040 = 24=> 1032x = 24+2040=> x= \xa0= 2=> x=2 (Answer) | |