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If hcf of 65 and 117 is expressible in the form 65m-117 then find the value of m |
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Answer» Ji We have 117=65×1+52 65=52×1+13And 52=13×4+0Hence, H.C.F=13Therefore, 65m-117=13 m=130/65 m=2Now 65=13×5 117=3×3×13L.C.M=13×5×3×3=585 Do not take tension |
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