If HCF of 65 and 117 is expressible in the form of 65n-117 , find n

1.	If HCF of 65 and 117 is expressible in the form of 65n-117 , find n
Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:{tex}HCF =65m-117 {/tex}{tex}13=65m-117{/tex}{tex}65m=130{/tex}m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2

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