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If `K_(1)` and `K_(2)` are the equilibrium constants of the equilibria (a) and (b) respectivel, what is the relationship between the two constants ? (a) `SO_(2)+(1)/(2) O_(2)(g)hArr SO_(3)(g),K_(1)` (b) `2SO_(3)(g) hArr 2SO_(2)(g)+O_(2)(g),K_(2)`A. `(K_(1))^(2)=(1)/(K_(2))`B. `K_(2)=(K_(1))^(2)`C. `K_(1)=(1)/(K_(2))`D. `K_(1)=K_(2)` |
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Answer» Correct Answer - A `(a) SO_(2)(g)+(1)/(2)O_(2)hArr SO_(3)(g), K_(1)` `(b) 2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g),K_(2)` `(K_(1))^(2)=(1)/(K_(2))` or `K_(1)=sqrt((1)/(K_(2)))` |
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