If k+1,3,4k+2 be any three consecutive terms of an AP find the value o

1.	If k+1,3,4k+2 be any three consecutive terms of an AP find the value of k?
Answer» K=3/5 hoga 1st term t1 = (k + 1).2nd term t2 = 3k.3rd term t3 = (4k + 2).Given that t1,t2,t3 are in AP.We know that when they are in AP, their common difference will be:t2 - t1 = t3 - t23k - (k + 1) = (4k + 2) - 3k3k - k - 1 = 4k + 2 - 3k2k - 1 = k + 22k = k + 2 + 12k = k + 32k - k = 3k = 3.Therefore the value of k = 3.

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