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If `lim_(x->oo)((x^2+x+1)/(x+1) -ax-b)=4` then a= ? b=? |
Answer» `lim_(x->oo)((x^2+x+1-ax^2-ax-bx-b)/(x+1))=4` `lim_(x->oo)((x+1-2ax-a-b)/1)=4` `lim_(x->oo)((x(2-2a)+1-a-b)/1)=4` 2-2a=0 a=1 1-a-b=4 a+b=-3 b=-4. |
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