If `(log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6)` in terms of `a` and `b` is equal to (a) `(2a+3b-1)/(5a+b-2)` (b) `(5a+b-1)/(3a+2b-2)` (c) `(3a+b-2)/(2a+3b-1)` (d) `(2a+5b-2)/(3a+b-1)`

If `(log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6)` in terms o

1.	If `(log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6)` in terms of `a` and `b` is equal to (a) `(2a+3b-1)/(5a+b-2)` (b) `(5a+b-1)/(3a+2b-2)` (c) `(3a+b-2)/(2a+3b-1)` (d) `(2a+5b-2)/(3a+b-1)`
Answer» `log_0.72^9.6` `log_10^9.6/log_10^0.72=(log_10^96-log_10^10)/(log_10^72-log_10^100)` `=(log_10 (2^53)-1)/(log_10 (2^33^2)-2)` `=(log_10 2^5+log_10 (3-1))/(log_10 2^3 +log_10 3^2 -2)` `=(5a+b-1)/(3a+2b-2)`.