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If `log_(2)(log_(2)(log_(2)x))=2`, then the number of digits in x, is `(log_(10)2=0.3010)`A. 7B. 6C. 5D. 4 |
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Answer» Correct Answer - C `log_(2)(log_(2)(log_(2)x))=2` `rArr log_(2)(log_(2)x)=4` `rArr log_(2)x=16` `rArr x=2^(16)` `therefore log_(10)x=16log_(10)2=16xx0.3010=4.8160` `therefore` Number of digits = 5 |
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