Solve : `root(4)(|x-3|^(x+1))=root(3)(|x-3|^(x-2))`.

1.	Solve : `root(4)(\|x-3\|^(x+1))=root(3)(\|x-3\|^(x-2))`.
Answer» Correct Answer - x = 4, 2 ; x = 11 `root(4)(\|x-3\|^(x+1))=root(3)(\|x-3\|^(x-2))` Taking log on both the sides `(x+1)/(4)log\|x-3\|=(x-2)/(3)log\|x-3\|` `rArr log\|x-3\|[(x+1)/(4)-(x-2)/(3)]=0` `rArr log\|x-3\|=0` or `[((x+1)/(4))-((x-2)/(3))]=0` `rArr x=4, 2` or x = 11

Discussion

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