InterviewSolution
Saved Bookmarks
| 1. |
The value of `6^(log_10 40)*5^(log_10 36)` isA. 200B. 216C. 432D. none of these |
|
Answer» Correct Answer - B We have `N = 6^(log_(10)40).5^(log_(10)36)` `therefore log_(10)N=log_(10)40 log_(10)6+log_(10)6+log_(10)36 log_(10)5` `=log_(10)6[log_(10)40+log_(10)25]` `= log_(10)6[log_(10)1000]` `= log_(10)(6)^(3)` `therefore N = 6^(3)=216` |
|