1.

The value of `6^(log_10 40)*5^(log_10 36)` isA. 200B. 216C. 432D. none of these

Answer» Correct Answer - B
We have `N = 6^(log_(10)40).5^(log_(10)36)`
`therefore log_(10)N=log_(10)40 log_(10)6+log_(10)6+log_(10)36 log_(10)5`
`=log_(10)6[log_(10)40+log_(10)25]`
`= log_(10)6[log_(10)1000]`
`= log_(10)(6)^(3)`
`therefore N = 6^(3)=216`


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