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If `x_(1)` and `x_(2)` are solution of the equation `log_(5)(log_(64)|x|+(25)^(x)-(1)/(2))=2x`, thenA. `x_(1)=2x_(2)`B. `x_(1)+x_(2)=0`C. `x_(1)=3x_(2)`D. `x_(1)x_(2)=64` |
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Answer» Correct Answer - B `log_(5)(log_(64)|x|+(25)^(x)-(1)/(2))=2x` `rArr log_(64)|x|+(25)^(x)-(1)/(2)=(25)^(x)` `rArr log_(64)|x|=(1)/(2)` `rArr |x|=8` `rArr x=-8,8` |
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