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If (n-2),(4n-1),(5n+1) are consecutive terms of an AP. Then find n. |
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Answer» Formula=2b=a+c,so 2(4n-1)=n-2+5n+1,so, 8n-2=6n-1,8n-6n=-1+2,so,2n=1,so,n=1/2 ans .... d=a2-a1d=a3-a2(4n-1)-(n-2)=(5n+1)-(4n-1)3n+1=n+2n=1/2 Batado koi |
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