If one of the quadratic polynomial f(x)=4 square-8k-9 is negative of the other. Find the value of k

If one of the quadratic polynomial f(x)=4 square-8k-9 is negative of t

1.	If one of the quadratic polynomial f(x)=4 square-8k-9 is negative of the other. Find the value of k
Answer» Let, the two zeroes of the polynomial f(x) = 4x2 - 8kx - 9 be α and -α.Comparing f(x) = 4x2\xa0- 8kx - 9 with ax2+bx+c we geta = 4; b = -8k and c = -9.Sum of the zeroes = α + (-α) ={tex}-\\frac ba=\\;-\\frac{-8k}4 {/tex}0 = 2kk = 0