Saved Bookmarks
| 1. |
If one root of the quadiatic equation 6xsquare -x-k=0 is 2/3 , this find the value of k |
|
Answer» 8/3-2/3=2 hota hain bhai Sorry the answer is 2 K= 2 6×2/3×2/3-2/3-k=0. 8/3-2/3-k=0. 7/3-k=0. K=7/3 2 |
|