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If one root of the quadratic Equation 2xsq+kx-6=0 is 2 then find the value of k+1. |
| Answer» As we know that root of an equation is one of the values which satisfies the equation, we have -2(2)2\xa0+ 2k - 6 =08+2k-6=02k+2=02 (k+1)=0k+1=0 Ans.\xa0 | |