If one solution of 3x2-8x-(2k+1) is seven times the other, find the va

1.	If one solution of 3x2-8x-(2k+1) is seven times the other, find the value of k
Answer» p(x)=3x²-2k+1zeroes=α,7αsum of zeroes= - b/aα+7α= -(2k/3)8α=2k/38α×3=2k24∝=2kk=12∝ (1)product of zeroes= c/a∝×7∝=1/37∝²=1/3∝²=1/(3×7)∝²=1/21∝=±1/√21∵∝=±1/√21∴k=12(±1/√21)k = ±12/√21

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