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if one zero of polynomial (a^2 +9)x^2 +13x +6a is reciprocal of the other ,fimd the value of a |
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Answer» Other zero=1/aproduct of zero= 1/a*a=1But product of zero= 6a/a^2+91=6a/a^2+9a^2+9=6aa^2-6a+9=0a^2 - 3a-3a+9=0a(a-3)-3(a-3) = 0(a-3) ( a-3)=0Hence,a=3 a is 3 HY |
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