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| 1. |
If one zero of polynomial (k-1)x^2+kx+1 is -3 , find the value of k. |
| Answer» X=-3 p(x)=(k-1)x^2+kx+1=0Putting the value of x in the p(x)P(x)=(k-1)(-3)^2+k(-3)+1=0 =(k-1)(9) - 3k +1=0 =9k-9-3k+1=0 =6k-8=0 =6k=8 =k=8/6 =k=4/3Hence, value of k is 4/3 | |