If one zero of quadtric polynomial x2+(a+1)x-6 is 2 , then what is the

1.	If one zero of quadtric polynomial x2+(a+1)x-6 is 2 , then what is the value of a?
Answer» As 2 is zero of given polynomial thenp(2) = 0=> (2)2 + (a+1)2 -6 = 0=> 4 + 2a + 2 - 6 = 0=> 0 + 2a = 0=> 2a = 0=> a = 0

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