If one zero of the polynomial 3x²-8x+2k+1 is seven times the other fi

1.	If one zero of the polynomial 3x²-8x+2k+1 is seven times the other find the value of k ?
Answer» Polynomial:- 3x²-8x+2k+1Let one zero be α Therefore second zero is 7αNow sum of zeroes= α+7α= -b/a=> 8α = -(-8)/3=> 8α = 8/3=> α = 1/3 —1Now product of zeroes =>α × 7α = c/a=>7α² =(2k+1)/3Putting value of α from —1=>7×(1/3)² = (2k+1)/3=>7×1/9= (2k+1)/3=>7/9=(2k+1)/3=>21=18k+9=>12=18k=> k = 12/18=> k= 2/3

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