If one zero of the polynomial (a^2+9)x^2+13x+6a is reciprocal of the other. Find the value of a

If one zero of the polynomial (a^2+9)x^2+13x+6a is reciprocal of the o

1.	If one zero of the polynomial (a^2+9)x^2+13x+6a is reciprocal of the other. Find the value of a
Answer» sum of roots = m + 1/m = -13/(a^2+9) and product of the roots = m x 1/m = 6a which gives 6a / (a^2+9)=16a = a^2+9a^2-6a+9=0 implies a^2-2 (a) (3) + 3^2=0 thus (a-3)^2=0 this a-3=0 and finally the value of a = 3 Let m and 1/m be the roots given roots are reciprocal of each other