If one zero of x^2-14x +13 is one then value of other zero is

1.	If one zero of x^2-14x +13 is one then value of other zero is
Answer» x2-14x +13\xa0\xa0x2-13x - x +13 = 0 x ( x - 13) - 1 ( x - 13) = 0 ( x - 13) ( x-1) = 0x - 13 = 0 and x- 1 = 0x = 13 and x = 1 Second zero is 13

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