If operator ‘a’ = 1 ∠120°. Then (1 – a) is equal to ____________(a) \(\sqrt{3}\)(b) \(\sqrt{3}\)∠-30°(c) \(\sqrt{3}\)∠30°(d) \(\sqrt{3}\)∠60°I got this question in my homework.My question is from Advanced Problems on Network Theory in section Network Theory and Complex Circuit Diagram of Network Theory

If operator ‘a’ = 1 ∠120°. Then (1 – a) is equal to _________

1.	If operator ‘a’ = 1 ∠120°. Then (1 – a) is equal to ____________(a) \(\sqrt{3}\)(b) \(\sqrt{3}\)∠-30°(c) \(\sqrt{3}\)∠30°(d) \(\sqrt{3}\)∠60°I got this question in my homework.My question is from Advanced Problems on Network Theory in section Network Theory and Complex Circuit Diagram of Network Theory
Answer» The correct option is (b) \(\SQRT{3}\)∠-30° Easy explanation: Given that, ‘a’ = 1 ∠120° So, 1 – a = 1 – 1∠120° = 1 + 0.5 – J 0.866 = 1.5 – j 0.866 = 3∠-30°.

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