If (p-1),(p-2),(3p-1)are in Ap,then p is equal to : 1.(4) 2.(-4)3.(2)4.(-2)

If (p-1),(p-2),(3p-1)are in Ap,then p is equal to : 1.(4) 2.(-4)3.(2)4

1.	If (p-1),(p-2),(3p-1)are in Ap,then p is equal to : 1.(4) 2.(-4)3.(2)4.(-2)
Answer» Join betternation.xyz This is a site where u can have a lot of friends and fun ? ? ? If you write p + 3 in place of p -2 then the answer is 4.p−1,p+3,3p−1 are in A.P.∴2(p+3)=p−1+3p−1⇒2p+6=4p−2⇒2p=8∴p=4 (p -2) - (p -1) = (3p -1) - (p -2)p -2 - p + 1 = 3p - 1 - p + 2-1 = 2p + 12p = -1 -1\xa02p = -2p = -2/2 = -1 But answer is 4 (p -2) - (p -1) = (3p -1) - (p -2)p -2 - p + 1 = 3p - 1 - p + 2-1 = 2p + 12p = -1 -1\xa02p = -2p = -2/2 = -1