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If sec 5A =cosec (A+36), where 5 A is an acute angle find the value of a??? ???? Solve fast |
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Answer» Tnxxx Ans is 9 Ans. 9 9 Sec 5A= cosec(A+36)Cosec(90-5A)=cosec(A+36) (secA=cosec(90-A)) 90-5A=A+3690-36=6A54=6AA=9 ans |
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