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| 1. |
If sec5A=cosec(A+36°),where 5A is an acute angle, find the value of A |
| Answer» Sec5A=cosec(A+36)Cosec(90-5A)=cosec(A+36)Both the cosec get cancelledAnd then,90-5A=A+3690-36=A+5A54=6AA=54/6A=9 | |