If secA=15/7 and A+B=90°. Find the value of cosecB.

1.	If secA=15/7 and A+B=90°. Find the value of cosecB.
Answer» Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15\xa0A + B = 90 or A = 90 - B\xa0CosA = Cos(90-B)\xa07/15 = SinB\xa0CosecB = 1/SinB = 1/ 7/15 = 15/7\xa0

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