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If secA=3/2 find 2cosA - tan^2A/sin^2A |
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Answer» 3 SecA=3/2=H/BBy Pythagoras theorem,H^2=P^2+B^29=P^2+4P^2=9-4P^2=5P=√5Therefore,According to the question,2*2/3-(√5/2)^2/(√5/3)4/3-(5/4)/(5/9)Now by taking LCM u can get the correcy answer! |
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