if secA+tanA=p ,then prove that sinA=(p square+1)/(p square-1)

1.	if secA+tanA=p ,then prove that sinA=(p square+1)/(p square-1)
Answer» answer mein sinA=p sq+1/p sq-1 ana ha vo kaise Multiply, ,(secA-tanA) on both sides... then solve yu will get the value of secA-tanA in terms of p... then solve the given eq. and the value yu have find to get the values of secA and tanA separately in terms of p..... then cosecA=secA/tanA put values..... yu will get cosecA= p²+1/p²-1....now, sinA=1/cosecA..... so, sinA=p sq. -1/p sq. +1

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