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If secA=x+1/4x, Prove that secA+tanA=2x or 1/2x |
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Answer» Thanks SecA=x+1/4x∴, sec²A=(x+1/4x)²=x²+2.x.1/4x+1/16x²=x²+1/2+1/16x²Now, sec²A-tan²A=1or, tan²A=sec²A-1∴, either,\xa0secA+tanA=x+1/4x+x-1/4x [when tanA=x+1/4x]=2x ______________or, secA+tanA=x+1/4x-x+1/4x [when tanA=-(x+1/4x)]=1/4x+1/4x=2/4x=1/2x Kl hi h shivangi Aacha ek baat btao physics ka test kal hai ya parso Okk,??? I will tell you the solution in class. Sushma didi please solve my problem |
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