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| 1. |
If secA = x+1/4x...then prove secA + tanA = 2x or 1/2x |
| Answer» Given:secA = x+1/4xsecA ^2 =(x+1/4x) ^2 (Squaring both the sides) tanA^2 + 1 = x^2 + 1/16x^2 + 1/2tanA^2 = x^2 + 1/16x^2 + 1/2 - 1tanA^2 = x^2 + 1/16x^2 - 1/2tanA ^2 = (x - 1/4x) ^2 tanA = x - 1/4x AS PER QUESTION :secA +tanA = x +1/4x + x - 1 /4x secA +tanA = x + x = 2x....HENCE PROVED | |