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If secB + tanB = x then the value of secB - tanB in term of x is? |
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Answer» 1/x 2÷26 SecB+tanB = x..(1)Sec2 B - tan2 B=1(SecB-tanB)(secB+tanB) = 1(SecB -tanB) (x) = 1 ( from (1))SecB - tan B = 1/x 1/x |
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