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If sin(2x +3y)=1 and cos (2x-3y)=√3\\2 find the value of x and y |
| Answer» Sin 2x+3y =1Sin 2x+3y =sin 902x+3y=90. eq 1Now Cos 2x-3y=√3/2Cos 2x-3y=cos302x-3y=30. Eq 2Adding 2x+3y+2x-3y=90+304x=120X=30. From eq12×30+3y=9060+3y=903y=90-60Y= 10 ie. X=30 ,y=10 answer | |