If sin 3A = cos( A-26), where 3A is an acute angle, find the value of

1.	If sin 3A = cos( A-26), where 3A is an acute angle, find the value of A
Answer» Sin 3A=cos (A-26)Cos(90-3A)=Cos (A-26)(90-3A)=(A-26)(90+26)=(3A+A)116=4AA=29

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