if sin A = 3/4 calculate sec A

1.	if sin A = 3/4 calculate sec A
Answer» SecA= 4√7/7 sin A = 3/4 P = 3H= 4B=? H² = P² + B²B²= 16 - 9B = √7 Sec A = H/B = 4/√74/√7 × √7/√7 = 4√7/7 So, Sec A = 4√7/7 Sin A= 3/2=p/hb²=h²-p²=b²=4-9=-5b=√-5SecA=h/b=2/-√5 Sec A = h / b = 4/√7 secA = 4/√7

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