If Sin(A-B) =0, Cos(A+B) =0, 0 degree

1.	If Sin(A-B) =0, Cos(A+B) =0, 0 degree
Answer» Sin(A-B) =0 Sin(A-B) =Sin0A-B=0A=BCos(A+B)=0Cos(A+B)=Cos90A+B=902A=90A=B=45Sin(A+B)=Sin(45+45)Sin90=1Cos(A-B)=Cos(45-45)Cos0=1

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