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| 1. |
If sin(A-B)=1/2,cos(A+B),0 degree |
| Answer» According to the question,\xa0{tex}\\sin (A - B) = \\frac{1}{2}{/tex}, therefore,\xa0{tex}A - B ={/tex} 30o ........ (1){tex}\\cos (A + B) = \\frac{1}{2}{/tex}, therefore, A + B = 60o ........ (2)Solving (1) and (2), we getA = 45o and B = 15o | |