If sin theta=1/2 show that 3 cos theta-4cos cube theta=0

1.	If sin theta=1/2 show that 3 cos theta-4cos cube theta=0
Answer» Sin theta = 1/2 => Sin theta = sin 30 => theta = 30 .. 3 × cos 30 - 4× cos cube 30 => 3× (√3/2) - 4(√3/2) 3 => 3√3/2 - 4 × 3√3/8 => 3√3/2 - 3√3/2 => 0 Now, RHS = LHS...So, it\'s prove..

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