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If sin theta=2/5, then find the value of 4+4tan² theta.

Answer» Sin A= 2/5 it means P = 2 and Hypotenuse = 5 . So base = √52\xa0-22\xa0= √25-4 = √21. So tan A= P/B = 2/√21So 4+4tan2A = 4+4(2/√21)2 = 4+4*4/21 = 4+16/21 = 84+16/21 = 100/21


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