If sin x=1/2 and cos x=\(\sqrt{3}\)/2, then find sin 2x.(a) \(\sqrt{3}\)/2(b) 1/2(c) 1/\(\sqrt{2}\)(d) 1This question was posed to me in quiz.The doubt is from Trigonometric Functions of Sum and Difference of Two Angles-2 in portion Trigonometric Functions of Mathematics – Class 11

If sin x=1/2 and cos x=\(\sqrt{3}\)/2, then find sin 2x.(a) \(\sqrt{3}

1.	If sin x=1/2 and cos x=\(\sqrt{3}\)/2, then find sin 2x.(a) \(\sqrt{3}\)/2(b) 1/2(c) 1/\(\sqrt{2}\)(d) 1This question was posed to me in quiz.The doubt is from Trigonometric Functions of Sum and Difference of Two Angles-2 in portion Trigonometric Functions of Mathematics – Class 11
Answer» The correct answer is (a) \(\sqrt{3}\)/2 For explanation: We KNOW, sin2x = 2 sin X cos x sin 2x = 21/2\(\sqrt{3}\)/2 sin 2x = \(\sqrt{3}\)/2.

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