If sin3A=cos(A-26°)where 3A is an acute angle,find value of A

1.	If sin3A=cos(A-26°)where 3A is an acute angle,find value of A
Answer» Sin3A=cos(A-26)Sin3A=sin263A=26A=26÷3 Thanks Bolne ki jarurat bahu hai SinA= cos(90-A) sin 3A = sin(90-A+26) Sin3A = sin(116-A)3A=116-A4A=116A=116/4A= 29 29 26

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