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If sinA = 12 / 13 , so find 1 / cos A = ??

Answer» Thanks for answering.
If sinA = 12 / 13 , so find 1 / cos A = ?sin2A + Cos2A = 1(12/13)2 + cos2A = 1144/169 + cos2A = 1cos2A = 1 - 144/169cos2A = (169-144)/169cos2A = 25/169cos A = 5/131/cosA = 13/5


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