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If sinA=3/4 then find the value of secA |
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Answer» Sec=4 by root 7 Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7 Diya soni you copied my answer Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7 Sin A = 3/4 =perpendicular /baseP=3H=4We can find tha base by pythagoras theorem in triangle ABCBA²=AC²-BC²BA²=4²-3²BA²=16-9BA²=7BA=√7SecA = hypotenuse /base SecA=4/√7 |
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